# Solve these 3 problems by Factoring?

(n+1)(n+9)=0

3x(4x+1)(x-5)=0

x^2+14x+48=0

### 1 Answer

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- Anonymous7 years agoFavourite answer
(n+1)(n+9)=0 [This is factored already.]

n+1=0 OR n+9=0 [Set each factor equal to 0.]

n=-1 OR n=-9 [Solve.]

{-1, -9}

3x(4x+1)(x-5)=0

3x=0 OR 4x+1=0 OR x-5=0

x=0 OR x=-1/4 OR x=5

{-1/4, 0, 5}

x²+14x+48=0

To factor a quadratic, ax²+bx+c=0, into (x+m)(x+n), m+n=b and m*n=c.

6 and 4 work for this equation.

(x+6)(x+4)=0 [Factor.]

x+6=0 OR x+4=0

x=-6 OR x=-4

{-6, -4}

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