Solve these 3 problems by Factoring?

(n+1)(n+9)=0

3x(4x+1)(x-5)=0

x^2+14x+48=0

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  • Anonymous
    7 years ago
    Favourite answer

    (n+1)(n+9)=0 [This is factored already.]

    n+1=0 OR n+9=0 [Set each factor equal to 0.]

    n=-1 OR n=-9 [Solve.]

    {-1, -9}

    3x(4x+1)(x-5)=0

    3x=0 OR 4x+1=0 OR x-5=0

    x=0 OR x=-1/4 OR x=5

    {-1/4, 0, 5}

    x²+14x+48=0

    To factor a quadratic, ax²+bx+c=0, into (x+m)(x+n), m+n=b and m*n=c.

    6 and 4 work for this equation.

    (x+6)(x+4)=0 [Factor.]

    x+6=0 OR x+4=0

    x=-6 OR x=-4

    {-6, -4}

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