CHEMISTRY HELP!? PERCENT ERROR?
0.003109 mol Fe^2+ X 55.85g/mol Fe (atomic weight) = 1.736gFe
is that correct?
e. if original sample weight was 1.4751g what is the calculated % of Fe^2+ in the sample based on your answer to question d?
percent yield right? so actual/thero 1.736g Fe/1.4751g Fe X 100% = 111.71%??
f. if actual percent of Fe^2+ in the sample is 13.25%, what is the percent error?
im stuck on this one, i might have did everything wrong, please help! i know percent error is actual - thero / thero X 100%. so do i just use my percent yield to subtract it from the 13.25%? IDK! HELP!
0.003109 moles of Fe^+2 X 55.85 g/mol Fe^+2