Pope
Lv 7
Pope asked in Science & MathematicsMathematics · 10 years ago

Chords bisected by a point?

Curve S and point P are defined below.

S: 21x² + y² - 168x + 40y - 734 = 0

P(7, -29)

How many chords of S are bisected by point P? Derive the equations of those chords.

3 Answers

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  • 10 years ago
    Favourite answer

    The equation S can be equivalently written as

    (x - 4)^2 / 70 + (y + 20)^2 / 1470 = 1

    To simplify we move the center to the origin (call the equation E),

    E: x^2 / 70 + y^2 / 1470 = 1

    We move the point P[ 7, - 29 ] the same amount (call it Q):

    Q[ 3, - 9 ]

    Using the parametrization of ellipse, a point on E (call it R) is expressed as

    R[ √70 (h^2 - 1) / (h^2 + 1), 14√30 h / (h^2 + 1) ]

    If we call another point U, RU must be bisected by Q, so the coordinates of U are

    U [ 3*2 - √70 ( h^2 - 1 ) / ( h^2 + 1 ), - 9*2 - 14√30 h / ( h^2 + 1 ) ]

    = [ ( ( 6 - √70) h^2 + ( 6 + √70 ) ) / ( h^2 + 1) , ( - 18h^2 - 14√30 h - 18 ) / ( h^2 + 1 ) ]

    U must be on E, so

    21 { ( ( 6 - √70) h^2 + ( 6 + √70 ) ) / ( h^2 + 1) }^2 + { ( - 18h^2 - 14√30 h - 18 ) / ( h^2 + 1 ) }^2 = 1470

    http://www.wolframalpha.com/input/?i=21+%28+%28+%2...

    h = ( 20√10 + 7√30 ) / ( 7√70 - 30 )

    or h = ( - 20√10 + 7√30 ) / ( 7√70 - 30 )

    When h = ( 20√10 + 7√30 ) / ( 7√70 - 30 ),

    R = [ 3 + 2√(30/7), 2√210 - 9 ], U = [ 3 - 2√(30/7), - 2√210 - 9 ]

    When h = ( - 20√10 + 7√30 ) / ( 7√70 - 30 ),

    R = [ 3 - 2sqrt(30/7), - 2 sqrt(210)-9 ], U = [ 3 + 2sqrt(30/7), 2 sqrt(210)-9 ]

    Equation for line RU is

    http://www4a.wolframalpha.com/input/?i=line+throug...

    RU: - 7x + y + 30 = 0

    We translated P and E at the start, so we translate RU back. Finally, equation of our chord of S that is bisected by P is

    - 7( x - 4 ) + ( y + 20 ) + 30 = 0

    - 7x + y + 78 = 0

    ***

    Source(s): Rational parametrization for circles: http://www.youtube.com/watch?v=Ui8OvmzDn7o&playnex... J function (a way to avoid fraction when calculating the join of points, and the meet of lines) example at 37:30, proof at 28:47: http://www.youtube.com/watch?v=tk58sBLWzHk
  • Tim L
    Lv 5
    10 years ago

    The curve is an ellipse, so the number of correct answers will be limited.

    Really, you have 2 equations to work with. The first one is the one you described. The 2nd is the midpoint formula. If (x1, y1) and (x2,y2) are the points on the ellipse, then

    SQRT((x1-7)^2 + (y1+29)^2) = SQRT(x2-7)^2 + (y2+29)^2.

    I'd work from there.

  • 10 years ago

    I could only find one so far (still hunting):

    y + 29 = 7.008055(x – 7)

    Cheers! ☺

    .

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