Question on partial derivatives?

Find the partial derivative ∂z / ∂x and ∂z / ∂y of the following function:

z = e^y sin (3x +2)

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  • TomV
    Lv 7
    10 years ago
    Favourite answer

    z = e^y sin (3x +2)

    ∂z/∂x = 3(e^y)cos(3x+2)

    ∂z/∂y = (e^y)sin(3x+2)

  • Anonymous
    10 years ago

    dz/dx = e^y cos (3x + 2) . d/dx (3x+2)

    = e^y cos (3x + 2) . 3

    = 3e^y cos (3x + 2)

    for dz/dy , simply that's the answer --> e^y cos (3x +

    x0

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