why is the chemical formula for vanadium (v) oxide V2O5?
if you were given the problem how would you know there is a 2 after the v
- Old Science GuyLv 710 years agoFavourite answer
V+5 and O-2
criss-cross the numbers without the signs
reduce to lowest possible whole number ration (already there)
this is the empirical formula
- Anonymous10 years ago
The (v) means that vanadium has an oxidation number of 5. (V is the roman numeral for 5).
Oxygen always has an oxidation number of -2.
The oxidation number of a compound always equals the charge of the compound. Here, the compound has no overall charge so it equals 0.
If there was only one vanadium, then the oxidation number would be 5 and you wouldn't be able to balance that out with oxygens because the 2 oxygens would make the overall oxidation number -1 and 3 oxygens would make the overall oxidation number +1. We want it to be 0.
Therefore we have two vanadium atoms, which have an oxidation number of +10 altogether.
We want the overall oxidation number to be 0 so we will have 5 oxygens, each at -2, to get -10 altogether.
- Dr.ALv 710 years ago
Vanadium (V) oxide means that vanadium has oxidation number +5
because oxygen has oxidation number -2 and for neutral species the sum of oxidation numbers times the number of each kind of atoms adds up to zero the formula is V2O5
check ; [ 5 ( +2)] + [5 (-2)]= 0
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