# why is the chemical formula for vanadium (v) oxide V2O5?

if you were given the problem how would you know there is a 2 after the v

Relevance

V+5 and O-2

criss-cross the numbers without the signs

V2O5

reduce to lowest possible whole number ration (already there)

this is the empirical formula

• Anonymous
9 years ago

The (v) means that vanadium has an oxidation number of 5. (V is the roman numeral for 5).

Oxygen always has an oxidation number of -2.

The oxidation number of a compound always equals the charge of the compound. Here, the compound has no overall charge so it equals 0.

If there was only one vanadium, then the oxidation number would be 5 and you wouldn't be able to balance that out with oxygens because the 2 oxygens would make the overall oxidation number -1 and 3 oxygens would make the overall oxidation number +1. We want it to be 0.

Therefore we have two vanadium atoms, which have an oxidation number of +10 altogether.

We want the overall oxidation number to be 0 so we will have 5 oxygens, each at -2, to get -10 altogether.

because oxygen has oxidation number -2 and for neutral species the sum of oxidation numbers times the number of each kind of atoms adds up to zero the formula is V2O5

check ; [ 5 ( +2)] + [5 (-2)]= 0

RE:

why is the chemical formula for vanadium (v) oxide V2O5?

if you were given the problem how would you know there is a 2 after the v

Source(s): chemical formula vanadium oxide v2o5: https://biturl.im/8on93