• ### Rational Function Help?

David, you need to tell us where you're stuck on each problem. Asking us to do the entire problem for you is cheating, not "help". Show us what you tried, how far you got, and we'll get you over the rough spots. In general, a function is discontinuous when a denominator is 0. You tell whether it's increasing or decreasing... show more
David, you need to tell us where you're stuck on each problem. Asking us to do the entire problem for you is cheating, not "help". Show us what you tried, how far you got, and we'll get you over the rough spots. In general, a function is discontinuous when a denominator is 0. You tell whether it's increasing or decreasing by taking the first derivative. The asymptotes are what you get when you set x to ±∞ and let the lower-order terms disappear. For instance, in the first one, you get a discontinuity where x-2 = 0 (that's the denominator). For an asymptote, set x = ∞ In the denominator, ∞-2 = ∞ Let the "-2" disappear, leaving x^2 / x as the asymptote. I expect that you can simplify that expression. I'll leave the derivatives to you. Do likewise on the second function.
1 answer · Homework Help · 5 years ago
• ### How do you find the x and y-intercepts for this function?

Plug in 0 for x and solve; that gives you the y-intercept. Plug in 0 for y and solve; that gives you the x-intercept.
Plug in 0 for x and solve; that gives you the y-intercept. Plug in 0 for y and solve; that gives you the x-intercept.
1 answer · Homework Help · 5 years ago
• ### Physics Homework Help?

Best answer: The plane must travel a distance of (59.7m + 25.0m) to clear the intersection. Use your distance formula to compute how much time it takes ... but set the zero point to when it clears the intersection. d = 1/2 a t^2 + v0 t + d0 You're given d0 = 59.7m + 25.0m v0 = 65m/s a = -5.1m/s^2 Set d = 0 and solve for t.
Best answer: The plane must travel a distance of (59.7m + 25.0m) to clear the intersection. Use your distance formula to compute how much time it takes ... but set the zero point to when it clears the intersection. d = 1/2 a t^2 + v0 t + d0 You're given d0 = 59.7m + 25.0m v0 = 65m/s a = -5.1m/s^2 Set d = 0 and solve for t.
1 answer · Homework Help · 5 years ago
• ### Find K that would make the integral converge?

Best answer: I don't think you got the problem quite correct: assuming that k is a constant, the integral converges, regardless of the value of k. What you have to do is to solve the equation: derive the indefinite integral in terms of k: integral {k x^(-3) } dx k x^(-2) / -2 + C -k / (2 x^2) + C Now evaluate that at x=2 and... show more
Best answer: I don't think you got the problem quite correct: assuming that k is a constant, the integral converges, regardless of the value of k. What you have to do is to solve the equation: derive the indefinite integral in terms of k: integral {k x^(-3) } dx k x^(-2) / -2 + C -k / (2 x^2) + C Now evaluate that at x=2 and x=∞. Subtract and set the difference to 10; the "C" terms cancel. Since one of the remaining terms is 0, it's pretty simply to solve for k.
1 answer · Homework Help · 6 years ago
• ### Mass chemistry question?

Best answer: This is a simple proportion: 25.2 g / 20.0 mL = x / 46 mL Solve for x and do the arithmetic. See how that works?
Best answer: This is a simple proportion: 25.2 g / 20.0 mL = x / 46 mL Solve for x and do the arithmetic. See how that works?
1 answer · Homework Help · 6 years ago
• ### Is this Equation a polynomial?

Best answer: Where are you stuck on this? Multiply it out and see how it fits your definition of a polynomial. Are all the terms in integral powers of x, or not? If so, what is the highest power of x?
Best answer: Where are you stuck on this? Multiply it out and see how it fits your definition of a polynomial. Are all the terms in integral powers of x, or not? If so, what is the highest power of x?
1 answer · Homework Help · 6 years ago
• ### How do you find the measure of the interior angle of a regular nonagon?

Best answer: The same as you do for any regular figure. The sum of the exterior angles is always 360°. An interior angle is the supplement of an exterior angle. A = 180 - (360 / N) ... where N is the number of sides. Plug in the "9", do the arithmetic, and there's your answer.
Best answer: The same as you do for any regular figure. The sum of the exterior angles is always 360°. An interior angle is the supplement of an exterior angle. A = 180 - (360 / N) ... where N is the number of sides. Plug in the "9", do the arithmetic, and there's your answer.
1 answer · Homework Help · 6 years ago

The formula for the monthly payment is in your textbook, or easily found on line. Since you're required to check both of these before posting here, I'm really puzzled as to where you're stuck. Simply search for "loan amortization", ignore the BizPlenty links, and take your pick form the first page of... show more
The formula for the monthly payment is in your textbook, or easily found on line. Since you're required to check both of these before posting here, I'm really puzzled as to where you're stuck. Simply search for "loan amortization", ignore the BizPlenty links, and take your pick form the first page of hits. http://www.amortization-calc.com/ http://bretwhissel.net/amortization/
3 answers · Homework Help · 6 years ago

Best answer: The formula for the monthly payment is in your textbook, or easily found on line. Since you're required to check both of these before posting here, I'm really puzzled as to where you're stuck. Simply search for "loan amortization", ignore the BizPlenty links, and take your pick form the first page of... show more
Best answer: The formula for the monthly payment is in your textbook, or easily found on line. Since you're required to check both of these before posting here, I'm really puzzled as to where you're stuck. Simply search for "loan amortization", ignore the BizPlenty links, and take your pick form the first page of hits. http://www.amortization-calc.com/ http://bretwhissel.net/amortization/
Homework Help · 6 years ago
• ### Algebra graph problem, HELP?

Best answer: Parallel lines have the same slope. In general, it's easiest if you change the equation to slope-intercept form for this sort of problem. Solve for y: y = -2x - 5 slope = -2, intercept = -5 You need a slope of -2 still, but an intercept of 2. That equation is y = -2x + 2 Now, just work this back into standard form, and... show more
Best answer: Parallel lines have the same slope. In general, it's easiest if you change the equation to slope-intercept form for this sort of problem. Solve for y: y = -2x - 5 slope = -2, intercept = -5 You need a slope of -2 still, but an intercept of 2. That equation is y = -2x + 2 Now, just work this back into standard form, and there's you're answer.
1 answer · Homework Help · 6 years ago

Best answer: I'd be happy to *help*, but you haven't explained where you're stuck. The process is pretty much the same for both: (1) Find the mean: add up the numbers and divide by the count. (2) Find the variance: subtract each number from the mean, square those differences, and add the squares. (3) The standard deviation is just the... show more
Best answer: I'd be happy to *help*, but you haven't explained where you're stuck. The process is pretty much the same for both: (1) Find the mean: add up the numbers and divide by the count. (2) Find the variance: subtract each number from the mean, square those differences, and add the squares. (3) The standard deviation is just the square root of the variance. Does that get you going?
1 answer · Homework Help · 6 years ago
• ### What is decolonisation?

Best answer: http://dictionary.reference.com/browse/d... For "how they did it", look in any encyclopedia for the history of Viet Nam.
Best answer: http://dictionary.reference.com/browse/d... For "how they did it", look in any encyclopedia for the history of Viet Nam.
1 answer · Homework Help · 6 years ago
• ### Math - Rate, Distance, Time (I think)?

Best answer: d = rt d = 330 miles r = 55 mph Plug in the given numbers, solve for t.
Best answer: d = rt d = 330 miles r = 55 mph Plug in the given numbers, solve for t.
1 answer · Homework Help · 6 years ago
• ### I need help. Can I be pregnant? Please?

Assuming that your periods were normal, then no, you are not pregnant. Your body shed the uterine lining needed to support a fetus -- and did it twice. Had there been a fertilized egg inside you, it would have been flushed out with the rest of the flow. However, do note that you're flirting with the possibility here. Some sperm are... show more
Assuming that your periods were normal, then no, you are not pregnant. Your body shed the uterine lining needed to support a fetus -- and did it twice. Had there been a fertilized egg inside you, it would have been flushed out with the rest of the flow. However, do note that you're flirting with the possibility here. Some sperm are released before ejaculation, in the drops of pre-ejaculate he produces. The chances are notably lower, but it's still possible. I strongly recommend that you get a copy of "Our Bodies, Our Selves" or similar reference book. This is sort of a owner's manual for the female body. I used it heavily when I was on a telephone crisis line, and I've given a copy to each of my close female partners, as well as to each of my children. There is a lot of great information in there for dealing with the various aspects of your body and your relationships to others.
6 answers · Pregnancy · 5 years ago
• ### Irregular Functions help?

Best answer: First of all, we need to characterize the position in terms of the origin: the zero points of time and position. The problem statement covers the twelve seconds before the bus gets to the middle of the intersection (position zero). Those are times -12 to 0. -12 <= t <= -9 . . . this is the 3-second sitting period, all at... show more
Best answer: First of all, we need to characterize the position in terms of the origin: the zero points of time and position. The problem statement covers the twelve seconds before the bus gets to the middle of the intersection (position zero). Those are times -12 to 0. -12 <= t <= -9 . . . this is the 3-second sitting period, all at distance 330. This segment of the graph is horizontal. -9 <= t <= -4 . . . . this is the 5-second interval at 30 ft/s; the bus travels from (-9, 330) to (-4, r), where "r" is the new distance: 330 ft - 30 ft/s * 5 s = 330 ft - 150 ft = 180 ft. Use the two-point formula to get the slope (which had better be 30) and virtual intercept of this segment. -4 <= t . . . . . . . . .this is the remainder of the bus's motion. You know that the bus travels in linear fashion from (-4, 180) to (0, 0) and keeps going. Again, use the two-point formula. Most notably, make sure that you use absolute value on the distance calculation to ensure that the distance is expressed as a positive number. You will need this on the last portion; there is a flex point at (0,0), when the bus goes from "before" to "after" the intersection.\ I can't really help with the second part -- you haven't specified the graphing tool you're using. However, I hope that the above set-up will help you work your way through the tool.
1 answer · Homework Help · 6 years ago
• ### What do people compare the Industrial Revolution to?

Best answer: That depends on the paradigm. In most instances, it's compared to either the feudal period or the information revolution.
Best answer: That depends on the paradigm. In most instances, it's compared to either the feudal period or the information revolution.
1 answer · Homework Help · 6 years ago
• ### Please can anybody solve this question?

Best answer: The dollar gain or loss depends on the size of your short; the problem gives no quantity. For a moment, let's assume one round lot, 100 shares. In essence, you sell 100 shares of EXCG that you don't have. You put up 55% of the \$286*100 for the virtual transaction of buying the shares. The other 45% (plus the \$20 transaction... show more
Best answer: The dollar gain or loss depends on the size of your short; the problem gives no quantity. For a moment, let's assume one round lot, 100 shares. In essence, you sell 100 shares of EXCG that you don't have. You put up 55% of the \$286*100 for the virtual transaction of buying the shares. The other 45% (plus the \$20 transaction fee) is what you borrow from CP. You pay 9% of this borrowed amount in interest. At the end of the year, you cover the short sale: you claim a gross profit of 100 * (\$286 - \$54). You also subtract the amount borrowed, the 9% interest on that amount, and another \$20 transaction fee. Can you take it from there?
1 answer · Homework Help · 6 years ago
• ### Statistics homework question?

Best answer: How many permutations are there of the three numbers? (3!) How many total possible draws are there for the lottery "answer"? (I expect it's 10^3) Divide those to get the probability of winning. Multiply that by the amount won (\$80), and that's your expected return on the \$1 bet. The net expectation is -\$1 +... show more
Best answer: How many permutations are there of the three numbers? (3!) How many total possible draws are there for the lottery "answer"? (I expect it's 10^3) Divide those to get the probability of winning. Multiply that by the amount won (\$80), and that's your expected return on the \$1 bet. The net expectation is -\$1 + expected_return.
1 answer · Homework Help · 6 years ago
• ### Sin3Q = 3sinQ - 4sin^3Q?

Best answer: (1) substitute Q for each of A, B, and C. This gives you sin 3Q = 3 sinQ cos^2Q - sin^3 Q sin 3Q = sinQ (3 cos^2Q - sin^2 Q) (2) replace cos^2Q with (1 - sin^2 Q) and simplify.
Best answer: (1) substitute Q for each of A, B, and C. This gives you sin 3Q = 3 sinQ cos^2Q - sin^3 Q sin 3Q = sinQ (3 cos^2Q - sin^2 Q) (2) replace cos^2Q with (1 - sin^2 Q) and simplify.
1 answer · Homework Help · 6 years ago
• ### Need ask info help? please...?

Best answer: Let me see whether I follow your string of events correctly. I'm not certain, since you departed from English (the official language of this forum). (1) You posted a question to something called "Ask a Question", whatever that is. (2) You kept posting the question, instead of waiting a reasonable amount of time -- where... show more