Can you factor these for me? Please show all steps!?

Question

x2-x-6=0 (The 2 is an exponent)

x2+5x+4=0 (The 2 is an exponent)

x2-4x-5=0 (The 2 is an exponent, they're all going to be that way so you get the point)

x2+x-12=0

x2-3x-10=0

x2+7x+12=0

x2+2x-15=0

x2-9x+14=0

x2-7x-18=0

x2+4x-45=0

x2+9x+18=0

x2-8x+15=0

x2+6x+5=0

I might ask questions about them so be prepared! ;)

Answer 1

Best Answer - Chosen by Voters

Hi,

For problems starting with x², look at the last sign. If it is positive, find factors of the constant (the last number) that add to the middle number. If the last sign is negative, find
factors of the constant (the last number) that subtract to the middle number.

x2-x-6=0
(x - 3)(x + 2) = 0
x = 3 or -2

x2+5x+4=0
(x + 4)(x + 1) = 0
x = -4 or -1

x2-4x-5=0
(x - 5)(x + 1) = 0
x = 5 or x = -1

x2+x-12=0
(x + 4)(x - 3) = 0
x = -4 or x = 3

x2-3x-10=0
(x - 5)(x + 2) = 0
x = 5 or x = -2

x2+7x+12=0
(x + 4)(x + 3) = 0
x = -4 or x = -3

x2+2x-15=0
(x + 5)(x - 3) = 0
x = -5 or x = 3

x2-9x+14=0
(x - 7)(x - 2) = 0
x = 7 or x = 2

x2-7x-18=0
(x - 9)(x + 2) = 0
x = 9 or x = -2

x2+4x-45=0
(x + 9)(x - 5) = 0
x = -9 or x = 5

x2+9x+18=0
(x + 6)(x + 3) = 0
x = -6 or x = -3

x2-8x+15=0
(x - 5)(x - 3) = 0
x = 5 or x = 3

x2+6x+5=0
(x + 5)(x + 1) = 0
x = -5 or x = -1

I hope that helps!! :-)

Answer 2

I will teach you how to do this. The answers are in the back of your text book.

eg. x^2 + 5x +6 = 0

( x )( x ) = 0 First what to multiply to get x^2 x * x = x^2

( x + 3 )( x +2 ) = 0 What two numbers have a product of 6 but add to 5.
Answer 3 and 2

Therefore x+3 =0 or x+2 = 0 So x = -3 or -2

x^2 - 3x + 10 = 0

( x - 5 )( x +2 ) =0 x * x = x^2 , -5 * 2 = -10 , -5 +2 =-3

Therefore x-5 =0 or x+2 = 0

so x = 5 or -2

Answer 3

You are being asked questions about them and you are NOT PREPARED !

These are basic and simple trinomial factoring problems. You should be able to do these. If you really can't do any of these, then you must go to your teacher. Obviously, the concept of using your text book is not in your repertoire !

You will have to pass tests on this material. I suggest you learn it !

QED

Answer 4

x^2 - x - 6 = 0 Factor (x +2)(x - 3)
x^2 + 5x + 4 = 0 Factor (x + 4)(x + 1)
x^2 + x - 12 = 0 Factor (x + 4)(x - 3)
x^2 - 3x - 10 = 0 Factor (x - 5)(x + 2)
x^2 + 7x + 12 = 0 Factor (x+3)(x + 4)
x^2 + 2x - 15 = 0 Factor (x + 7)(x - 5)
x^2 - 9x + 14 = 0 Factor (x - 7)(x - 2)
x^2 - 7x -18 = 0 Factor (x - 9)(x + 2)
x^2 + 4x - 45 = 0 Factor (x + 9)(x - 5)
x^2 + 9x + 18 = 0 Factor (x = 6)(x + 3)
x^2 -8x + 15 = 0 Factor (x - 5)(x - 3)
x^2 + 6x + 5 = 0 Factor (x = 5)(x + 1)

OK all done

Answer 5

x2+5x+4=0=(x+4)(x+1)
x2-4x-5=0=(x-5)(x+1)
x2+x-12=0 = (x+4)(x-3)
x2-3x-10=0=(x-5)(x+2)
x^2 + x -12 = (x + 4)(x-3)
x^2 -9x +14 = (x-7)(x-2)
x2-7x-18=0 = (x-9)(x+2)
x2+4x-45=0 = (x+9)(x-5)
x2+9x+18=0 = (x+3)(x+6)
x2-8x+15=0 = (x-3)(x_5)
x2+6x+5=0 = (x+5)(x+1)

Answer 6

(x-3)(x+2)

(x+1)(x+4)

(x-5)(x+1)

(x+4)(x-3)

(x-5)(x+2)

(x+4)(x+3)

(x+5)(x-3)

(x-7)(x-2)

(x-9)(x+2)

(x+9)(x-5)

(x+3)(x+6)

(x-3)(x-5)

(x+1)(x+5)

Answer 7

wow if it was only one or 2 its okay but theres soo many. btw just by looking at them, they arent that hard to factor, just too time-consuming

Answer 8

seriously...all of these

Answer 9

too many!