• ## Discover

1. Home >
2. All Categories >
3. Science & Mathematics >
4. Mathematics >
5. Resolved Question
Member since:
26 October 2008
Total points:
184 (Level 1)

## Resolved Question

Show me another »

# Can you factor these for me? Please show all steps!?

x2-x-6=0 (The 2 is an exponent)

x2+5x+4=0 (The 2 is an exponent)

x2-4x-5=0 (The 2 is an exponent, they're all going to be that way so you get the point)

x2+x-12=0

x2-3x-10=0

x2+7x+12=0

x2+2x-15=0

x2-9x+14=0

x2-7x-18=0

x2+4x-45=0

x2+9x+18=0

x2-8x+15=0

x2+6x+5=0

Member since:
20 July 2006
Total points:
222,796 (Level 7)

## Best Answer - Chosen by Voters

Hi,

For problems starting with x², look at the last sign. If it is positive, find factors of the constant (the last number) that add to the middle number. If the last sign is negative, find
factors of the constant (the last number) that subtract to the middle number.

x2-x-6=0
(x - 3)(x + 2) = 0
x = 3 or -2

x2+5x+4=0
(x + 4)(x + 1) = 0
x = -4 or -1

x2-4x-5=0
(x - 5)(x + 1) = 0
x = 5 or x = -1

x2+x-12=0
(x + 4)(x - 3) = 0
x = -4 or x = 3

x2-3x-10=0
(x - 5)(x + 2) = 0
x = 5 or x = -2

x2+7x+12=0
(x + 4)(x + 3) = 0
x = -4 or x = -3

x2+2x-15=0
(x + 5)(x - 3) = 0
x = -5 or x = 3

x2-9x+14=0
(x - 7)(x - 2) = 0
x = 7 or x = 2

x2-7x-18=0
(x - 9)(x + 2) = 0
x = 9 or x = -2

x2+4x-45=0
(x + 9)(x - 5) = 0
x = -9 or x = 5

x2+9x+18=0
(x + 6)(x + 3) = 0
x = -6 or x = -3

x2-8x+15=0
(x - 5)(x - 3) = 0
x = 5 or x = 3

x2+6x+5=0
(x + 5)(x + 1) = 0
x = -5 or x = -1

I hope that helps!! :-)

There are currently no comments for this question.

• by peabody
Member since:
02 November 2009
Total points:
50,774 (Level 7)
I will teach you how to do this. The answers are in the back of your text book.

eg. x^2 + 5x +6 = 0

( x )( x ) = 0 First what to multiply to get x^2 x * x = x^2

( x + 3 )( x +2 ) = 0 What two numbers have a product of 6 but add to 5.

Therefore x+3 =0 or x+2 = 0 So x = -3 or -2

x^2 - 3x + 10 = 0

( x - 5 )( x +2 ) =0 x * x = x^2 , -5 * 2 = -10 , -5 +2 =-3

Therefore x-5 =0 or x+2 = 0

so x = 5 or -2
• Member since:
20 September 2007
Total points:
231,175 (Level 7)
You are being asked questions about them and you are NOT PREPARED !

These are basic and simple trinomial factoring problems. You should be able to do these. If you really can't do any of these, then you must go to your teacher. Obviously, the concept of using your text book is not in your repertoire !

You will have to pass tests on this material. I suggest you learn it !

QED
• 1 person rated this as good
• Member since:
08 November 2009
Total points:
5,023 (Level 5)
x^2 - x - 6 = 0 Factor (x +2)(x - 3)
x^2 + 5x + 4 = 0 Factor (x + 4)(x + 1)
x^2 + x - 12 = 0 Factor (x + 4)(x - 3)
x^2 - 3x - 10 = 0 Factor (x - 5)(x + 2)
x^2 + 7x + 12 = 0 Factor (x+3)(x + 4)
x^2 + 2x - 15 = 0 Factor (x + 7)(x - 5)
x^2 - 9x + 14 = 0 Factor (x - 7)(x - 2)
x^2 - 7x -18 = 0 Factor (x - 9)(x + 2)
x^2 + 4x - 45 = 0 Factor (x + 9)(x - 5)
x^2 + 9x + 18 = 0 Factor (x = 6)(x + 3)
x^2 -8x + 15 = 0 Factor (x - 5)(x - 3)
x^2 + 6x + 5 = 0 Factor (x = 5)(x + 1)

OK all done
11% 1 Vote
• by Bo Q
Member since:
21 June 2009
Total points:
122 (Level 1)
x2+5x+4=0=(x+4)(x+1)
x2-4x-5=0=(x-5)(x+1)
x2+x-12=0 = (x+4)(x-3)
x2-3x-10=0=(x-5)(x+2)
x^2 + x -12 = (x + 4)(x-3)
x^2 -9x +14 = (x-7)(x-2)
x2-7x-18=0 = (x-9)(x+2)
x2+4x-45=0 = (x+9)(x-5)
x2+9x+18=0 = (x+3)(x+6)
x2-8x+15=0 = (x-3)(x_5)
x2+6x+5=0 = (x+5)(x+1)
• by Eng Ngee
Member since:
10 November 2009
Total points:
1,661 (Level 3)
(x-3)(x+2)

(x+1)(x+4)

(x-5)(x+1)

(x+4)(x-3)

(x-5)(x+2)

(x+4)(x+3)

(x+5)(x-3)

(x-7)(x-2)

(x-9)(x+2)

(x+9)(x-5)

(x+3)(x+6)

(x-3)(x-5)

(x+1)(x+5)
• Member since:
27 April 2008
Total points:
1,784 (Level 3)
wow if it was only one or 2 its okay but theres soo many. btw just by looking at them, they arent that hard to factor, just too time-consuming
11% 1 Vote
• 1 person rated this as good
• by Ash57
Member since:
12 October 2009
Total points:
1,559 (Level 3)
seriously...all of these
• 2 people rated this as good
• by ʎɥʇɐʞ
Member since:
04 April 2007
Total points:
7,223 (Level 5)
too many!